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Dissociate letter contact blocks before archiving

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Otherwise you can’t archive it.
This commit is contained in:
Chris Hill-Scott
2019-07-05 13:29:42 +01:00
parent ed6f9e4736
commit dd225fbc6e
3 changed files with 20 additions and 21 deletions
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16
tests/app/dao/test_service_letter_contact_dao.py
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@@ -209,16 +209,22 @@ def test_archive_letter_contact_does_not_archive_a_service_default_letter_contac
assert 'You cannot delete a default letter contact block' in str(e.value)
def test_archive_letter_contact_does_not_archive_a_template_default_letter_contact(notify_db_session):
def test_archive_letter_contact_does_dissociates_template_defaults_before_archiving(notify_db_session):
service = create_service()
create_letter_contact(service=service, contact_block='Edinburgh, ED1 1AA')
template_default = create_letter_contact(service=service, contact_block='Aberdeen, AB12 23X', is_default=False)
create_template(service=service, template_type='letter', reply_to=template_default.id)
associated_template_1 = create_template(service=service, template_type='letter', reply_to=template_default.id)
associated_template_2 = create_template(service=service, template_type='letter', reply_to=template_default.id)
with pytest.raises(ArchiveValidationError) as e:
archive_letter_contact(service.id, template_default.id)
assert associated_template_1.reply_to == template_default.id
assert associated_template_2.reply_to == template_default.id
assert template_default.archived is False
assert 'You cannot delete the default letter contact block for a template' in str(e.value)
archive_letter_contact(service.id, template_default.id)
assert associated_template_1.reply_to is None
assert associated_template_2.reply_to is None
assert template_default.archived is True
def test_dao_get_letter_contact_by_id(sample_service):