Got the SqlAlchemy query to work

This commit is contained in:
Rebecca Law
2017-02-14 11:05:23 +00:00
parent 681f52b691
commit 1c6cfb9bc8

View File

@@ -1,6 +1,7 @@
import uuid
from sqlalchemy import (desc, text)
import sqlalchemy
from sqlalchemy import desc
from app import db
from app.models import (Template, TemplateHistory)
@@ -61,11 +62,21 @@ def dao_get_template_versions(service_id, template_id):
def dao_get_templates_by_for_cache(cache):
if not cache or len(cache) == 0:
return []
txt = "( " + " Union all ".join(
"select '{}'::text as template_id, {} as count".format(x.decode(),
y.decode()) for x, y in cache) + " ) as cache"
txt = "Select t.id as template_id, t.template_type, t.name, cache.count from templates t, " + \
txt + " where t.id::text = cache.template_id order by t.name"
stmt = text(txt)
return db.session.execute(stmt).fetchall()
# First create a subquery that is a union select of the cache values
# Then join templates to the subquery
cache_queries = [
db.session.query(sqlalchemy.sql.expression.bindparam("template_id" + str(i),
uuid.UUID(template_id.decode())).label('template_id'),
sqlalchemy.sql.expression.bindparam("count" + str(i), int(count.decode())).label('count'))
for i, (template_id, count) in enumerate(cache)]
cache_subq = cache_queries[0].union(*cache_queries[1:]).subquery()
query = db.session.query(Template.id.label('template_id'),
Template.template_type,
Template.name,
cache_subq.c.count.label('count')
).join(cache_subq,
Template.id == cache_subq.c.template_id
).order_by(Template.name)
return query.all()